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Answer: Correct! The probability of the first two questions drawn being history questions was ${\displaystyle \left(\frac{1}{6}\right)\left(\frac{4}{29}\right)=\frac{2}{87}}$ or about 0.023. For the third draw, there would be 28 cards remaining, 3 of which are history cards. For the third drawing the probability of drawing a history card is ${\displaystyle \frac{3}{38}}$. The probability of drawing history cards on the first three draws is ${\displaystyle \left(\frac{1}{6}\right)\left(\frac{4}{29}\right)\left(\frac{3}{28}\right)=\frac{1}{406}}$ or 0.002. Incorrect. The answer is ${\displaystyle \frac{1}{406}}$ or about 0.002. The probability of the first two questions drawn being history questions was ${\displaystyle \left(\frac{1}{6}\right)\left(\frac{4}{29}\right)=\frac{2}{87}}$ or about 0.023. For the third draw, there would be 28 cards remaining, 3 of which are history cards. For the third drawing the probability of drawing a history card is ${\displaystyle \frac{3}{38}}$. The probability of drawing history cards on the first three draws is ${\displaystyle \left(\frac{1}{6}\right)\left(\frac{4}{29}\right)\left(\frac{3}{28}\right)=\frac{1}{406}}$ or 0.002. Incorrect. Try again.