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Answer: Correct! The probability of drawing a history card on the first draw is ${\displaystyle \frac{5}{30}=\frac{1}{6}}$. After the first draw, there would be 29 cards remaining, 4 of which are history cards. For the second drawing the probability of not drawing a history card is ${\displaystyle \frac{25}{29}}$. So the probability of drawing a history card on the first draw, but not the second, is ${\displaystyle \left(\frac{1}{6}\right)\left(\frac{25}{29}\right)=\frac{25}{174}}$ or about 0.144. Incorrect. The probability of drawing a history card on the first draw is ${\displaystyle \frac{5}{30}=\frac{1}{6}}$. After the first draw, there would be 29 cards remaining, 4 of which are history cards. For the second drawing the probability of not drawing a history card is ${\displaystyle \frac{25}{29}}$. So the probability of drawing a history card on the first draw, but not the second, is ${\displaystyle \left(\frac{1}{6}\right)\left(\frac{25}{29}\right)=\frac{25}{174}}$ or about 0.144. Incorrect. Try again.